What are the vertical and horizontal asymptotes for the function 3x^2/x^2-4

vertical asymptotes: x = 2, x = -2

              horizontal asyptote: y = 3

Step-by-step explanation:

Vertical Asymptotes are the restrictions on "x", which is denoted by the denominator being unequal to zero.

x² - 4 = 0

(x + 2)(x - 2) = 0

x + 2 = 0      and       x - 2 = 0

     x = -2     and             x = -2

Horizontal Asymptotes are determined by the degree of the numerator (n) compared to the degree of the denominator (m) as follows:

In the given problem, the degree of both the numerator and denominator is 2 so horizontal asymptote is:

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.