The population of a pack of wolves is 88. the population is expected to grow at a rate of 2.5% each year. which function equation represents the population of the pack of wolves after t years? f(t)=88(0.025)^t f(t)=88(1.025)^t f(t)=88(1.25)^t f(t)=88(2.5)^t

Option B I think

Option B is correct.

represents the population of the pack of wolves after t years

Step-by-step explanation:

The exponential growth function is given by;

              ......[1]

where

a represented the initial value

r represents the rate(in decimal)

t represents the time in years

As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.

⇒ a = 88 and  r =2.5% = 0.025.

Substituting these values in equation [1], we have;

or

Therefore, the population model of the pack of wolves after t years is given by:  

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²