What is the nth term of the geometric sequence 4, 8, 16, 32, ?

tn = a*2^(n - 1)

Step-by-step explanation:

a = 4

r = 2

tn= a*2^(n-1)

Try it

t3 = 4*2^(3 -1)        Combine the power

t3 = 4 * 2^2            Find 2^2

t3 = 4 * 4                Multiply

t3 = 16                     Answer for t3

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9