Which binomial expressions are factors of 5x^3+8x^2-7x-6

x - 1 and x + 2

Step-by-step explanation:

By the factor theorem if (x - a) is a factor then f(a) = 0.

Try x - 1:_

f(1) =  5(1)^3 + 8(1)^2 - 7 - 6

= 5 + 8 - 7 - 7

= 0  so x - 1 is a factor

We can find the other factors by long division:-

            5x^2  + 13x + 6

x - 1 )    5x^3  + 8x^2  -  7x  -  6

           5x^3  -   5x^2

                        13x^2  -   7x

                         13x^2  -  13x

                                       6x - 6

                                        6x - 6

    5x^2  + 13x + 6   = (5x + 3)(x + 2)                          

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i