The exponential distribution is frequently applied to the waiting times between successes in a poisson process. if the number of calls received per hour by a telephone answering service is a poisson random variable with parameter î» = 6, we know that the time, in hours, between successive calls has an exponential distribution with parameter î² =1/6. what is the probability of waiting more than 15 minutes between any two successive calls?

P(x>15) = 0.9656

Step-by-step explanation:

No. of calls received is a poisson random variable with parameter = 6

mean = 6

And the waiting time between the phone calls received is exponentially distributed with parameter m = 1\6.

We need to find the waiting time more than 15 minutes.

1hour= 60 minutes

15 minutes= 0.214 hours.

P(x>x) = e^{-mx)

P(x>0.214) = e^{-0.214\6}

                 = 0.9656

answer: howdy

step-by-step explanation:

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.