What is the value of c when the value of the expression 2(3–5c) is 1 less than the value of the expression 4(1–c)?

The answer in fraction form is c = 1/2

The answer in decimal form is c = 0.5

Explanation:

Saying "A is 1 less than B" means A = B-1. So whatever B is, subtract 1 from it and you get the value of A.

Replace A with the expression 2(3-5c). Replace B with 4(1-c)

We go from this

A = B - 1

to this

2(3-5c) = 4(1-c) - 1

Let's isolate c

2(3-5c) = 4(1-c) - 1

2(3)+2(-5c) = 4(1)+4(-c) - 1

6-10c = 4 - 4c - 1

6-10c = 3 - 4c

6-3 = -4c+10c

3 = 6c

6c = 3

c = 3/6

c = 1/2

c = 0.5

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%

answer: 486in^2

step-by-step explanation: