X^2+y^2−10=0 write the values of y, for which the equation has sense.

y = 3

Step-by-step explanation:

The objective is to get 0 on the left side to equal the 0 on the right side. I'd like to do this by making the sum of x^2 and y^2 equal to 10. If (x^2+y^2) = 10, the -10 on the left side will cancel it out to equal 0.

1^2 = 1

3^3 = 9

1 + 9 = 10

Therefore, x is 1 and y is 3.

x^2 + y^2 - 10 = 0

1^2 + 3^2 - 10 - 0

1     +     9  - 10 = 0

10              -10 = 0

0 = 0

probability for j is 1/4

while

a is 1/6

answer: (3,11) is your answer.