Ajar containing only nickels and dimes contains a total of 60 coins. the value of all the coins in the jar is $4.45. solve by elimination to find the number of nickels and dimes that are in the jar.

The number of nickels and dimes that are in the jar is 31 and 29 respectively.

Given that,

Based on the above information, the calculation is as follows:

x + y = 60 (1)

5x + 10y = 445(2)

Here we multiply by 5 in equation 1

5x + 5y = 300

5x + 10y = 445

-5y = 145

y = 29

So, x = 60 - 29

= 31

Therefore we can conclude that the number of nickels and dimes that are in the jar is 31 and 29 respectively.

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31 nickels and 29 dimes

Step-by-step explanation:

Nickels (.05): x

Dimes (.10): y

 Value:     .05x + .10y = 4.45 →  -20(.05x + .10y = 4.45)   →   -x - 2y = -89

Quantity:        x  +    y  = 60   →       1(x  +    y  = 60)           →   x  + y = 60

                                                                                                       -y  = -29

                                                                                                        y  =  29

Next, substitute "29" for "y" into either equation and solve for "x":

x +  y  = 60

x + 29 = 60

x          = 31

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