Sherman goes golfing every 6^\text{th}6 th day and brad goes golfing every 7^\text{th}7 th day. if sherman and brad both went golfing today, how many days until they will go golfing on the same day again? days

42 days.

Step-by-step explanation:

We have been given that Sherman goes golfing every 6th day and Brad goes golfing every 7th day.

To find the number of days after that both will go golfing on the same day we will find LCM of 6 and 7.

Multiples of 6 are: 6, 12, 18, 24, 30, 36, 42, 48,..

Multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56,...

We can see that least common multiple of 6 and 7 is 42, therefore, both will go golfing on the same day again on 42nd day.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%