Nina made two investments: investment \text{a}a has a value of \$50$50 at the end of the first year and increases by 8\%8% per year. investment \text{b}b has a value of \$60$60 at the end of the first year and increases by \$3$3 per year. nina checks the value of her investments once a year, at the end of the year. what is the first year in which nina sees that investment \text{a}a's value exceeded investment \text{b}b's value?

6 years

Step-by-step explanation:

Given,

The amount of investment A  = $ 50,

Annual rate of interest = 8 %,

Thus, her amount after x years,

Now, the amount of investment B = $ 60,

Added amount per year = $ 3,

⇒ Added amount in x years = 3x,

Thus, Total amount after x years,

Since, Investment A's value exceeded investment B's value,

If,

By the below graph,

We found that,

x > 5.552

Hence, the first year at which the Investment A's value exceeded investment B's value is 6 years ( approx )

1. 8

2. 9

3. 20

4. 3

5. 17

6. 2.2

7. 11.25

8. 1

9. 14

10. 2

step-by-step explanation:

thats the first half