Abcd is a quadrilateral inscribed in a circle, as shown below: what equation can be used to solve for angle a? (x + 16) + (6x − 4) = 180 (x + 16) + (x) = 90 (x + 16) − (2x + 16) = 180 (x + 16) − (x) = 90 ! it will be greatly appreactated

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.