Which of the following is true for the graph of the quadratic function f(x)=3(x+2)(×-2)

A

Step-by-step explanation:

given y = 3(x + 2)(x - 2) = 3(x² - 4) = 3x² - 12

for the y- intercept let x = 0

f(0) = - 12 → y-intercept is the point (0, - 12) → True

for x-intercepts let y = 0

3(x + 2)(x - 2) = 0

x + 2 = 0 ⇒ x = - 2

x - 2 = 0 ⇒ x = 2

x- intercepts are (- 2, 0) and (2, 0) → not (0, - 12)

since f(x) = 3x² - 12 is symmetric about the y-axis

the vertex is at (0, - 12 ) → not (- 2, 2)

not me

step-by-step explanation:

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