If a chick eat 10 g a day. and daily 1 g increase i. e 11g on second day. what how much altogether would it be for a month.

It depends on the month

Step-by-step explanation:

mainly it depends on the month but if the month has 31 daysthen 352

Step-by-step explanation:

first you need to add 10+1=11 because the chick is eating both in one day, next save the second day's food, 11+10+1=22, you have taken out the second day which means there is now only 30 you are left with, multiply 11x30=330, then you bring back the second day of the month...330+22=352

11x30=330+22=352

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)