Which is the approximate solution for the system of equations x+5y=10 and 3x+y=1?

Step-by-step explanation:

Given system of equations :

x+5y=10 and 3x+y=1.

Let us solve the system of equation by substitution.

Solving second equation 3x+y=1 for y first.

3x+y=1.

Subtracting 3x from both sides, we get

3x-3x+y=1-3x

y = 1-3x.

Substituting y=1-3x in first equation x+5y=10, we get

x+ 5(1-3x) = 10.

x + 5 -15x =10

-14x +5 = 10.

Subtracting 5 from both sides, we get

-14x +5-5 = 10-5

-14x =5

Dividing by -14 on both sides, we get

-14x/-14=5/-14

x= -0.36.

Plugging x=-0.36 in second equation y=1-3x, we get

y = 1-3(-0.36) = 1+1.08 = 2.08.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.