Carla is wrapping a present in the box shown. how much wrapping paper does she need, not including overlap?
*it is a rectangular prism: 4in (height) 3in (width) 10in (length)

Carla needed 164 inches² wrapping paper to wrap the present.

Step-by-step explanation:

Given :  A rectangular prism having length 10 inch , width 3 inch and height 4 inch.

We have to find the length of wrapping paper does Carla need to wrap the present which is in form of given rectangular prism (not including overlap)

The length of wrapping paper needed will be equal to the total surface area of rectangular prism.

total surface area of rectangular prism = 2( lw +wh + hl)

Where l denotes length , w denotes width and h denotes height

Given length = 10 inch ,

width = 3 inch

height = 4 inch.

Substitute, we get,

total surface area of rectangular prism =2 (10× 3 + 3× 4 + 4 × 10 )

total surface area of rectangular prism =2 (30 + 12 + 40)

Total surface area of rectangular prism = 164 inches²

Thus, Carla needed 164 inches² wrapping paper to wrap the present.

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.