The amount, a, in milligrams, of radioactive material remaining in a container can be modeled by the exponential function a(t)=5(0.5)^0.25t where t is time, in years. based on this model how many years does it take for half of the original radioactive material to be left remaining?

4 years

Step-by-step explanation:

The exponent of 0.5 is 1 when t=4. So, half the original amount will be remaining when t=4.

b and c

step-by-step explanation:

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4