The length of a rectangle is six times its width. if the area of the rectangle is 486 in 2 , find its perimeter.

w - width

6w - length

486 in² - area of the rectangle

(w)(6w) = 6w² - area of the rectangle

The equation:

6w² = 486     divide both sides by 6

w² = 81 → w = √81

w = 9 in

l = 6w → l = (6)(9) → l = 54 in

The perimeter: P = 2l + 2w

P = 2(54) + 2(9) = 108 + 18 = 126 in

ok

step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!