If you have an equation of the form ax2 + c = 0, with a > 0, under what conditions will there be no real solutions?

If c>0, then the solution is imaginary, which is not a real solution.

Step-by-step explanation:

ax^2 + c = 0, with a > 0

Subtract c from each side

ax^2 +c-c = 0-c

ax^2 = -c

Divide each side by a

ax^2/a = -c/a

x^2 = -c/a

Take the square root of each side

sqrt(x^2) = sqrt(-c/a)

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The only way to have real square roots is for -c/a to be positive.

We know that a>0, so -c >0

-c>0

Divide each side by -1, remembering to flip the inequality

c<0

If c<0  we have real solutions

If c=0  then x=0 which is a real solution

If c>0, then the solution is imaginary, which is not a real solution.

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step-by-step explanation:

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the answer is:

the correct option is the option b.

to calculate the surface area of the right cylinder, we need to use the following formula:

from the picture we know that:

so, substituting and calculting we have:

hence, we have that the correct option is the option b.

have a nice day!