What is the average rate of change of the function over the interval x = 0 to x = 5? f(x)=4^2x+1 enter your answer, as a simplified fraction,

838860

Plug in x = 0 to find y = f(x)

f(x) = 4^(2x+1)

f(0) = 4^(2*0+1)

f(0) = 4

The point (0,4) is on the function curve

Plug in x = 5 and compute

f(x) = 4^(2x+1)

f(5) = 4^(2*5+1)

f(5) = 4194304

The point (5, 4194304) is on the function curve

Once you have these two points, you use the slope formula to compute the average rate of change

m = (y2-y1)/(x2-x1)

m = (4194304 - 4)/(5-0)

m = 838860

The slope of the line through the two points found earlier is m = 838860, so this is the average rate of change on f(x) for the interval from x = 0 to x = 5.

c

step-by-step explanation:

it's d

step-by-step explanation: