R(3, 2), s(5, -2), and t(6, 0) are the coordinates of a triangle's vertices. if the triangle is translated down 6 units, what are the coordinates of the image?

6 units down → subtract 6 from y-coordinate of each point.

R(3, 2) → R'(3, 2 - 6) = (3, -4)

S(5, -2) → S'(5, -2 - 6) = (5, -8)

T(6, 0) → T'(6, 0 - 6) = (6, -6)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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