Saheel has $20,000 property damage insurance and $5,000 comprehensive and collision insurance with a $500 deductible. one evening he slides on a patch of ice and hits a parked car, causing $4,500 worth of damage. the accident causes $1,750 of damage to his own car. how much will the insurance pay to fix both cars?

$5750

Step-by-step explanation:

Property damage insurance = $20,000

Comprehensive insurance = $5,000

Deductible = $500

Amount of Property damage caused by him by hitting a parked car = $4,500

Amount of Damage caused to his own car = $1,750

Since, the property damage of $4500 is within the property damage insurance limit of $20,000 and own damage of $1,750 is also within the comprehensive insurance limit of $5000, he'll be paid the entire amount excluding the compulsory deductible of $500.

So,

The amount paid by the insurance company to fix both cars = 4500+1750 - 500

= 6250 - 500

= $5750

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

he earned 78.75 in interest.

step-by-step explanation: