The velocity of a car increases from 2.0 m/s to 16.0 m/s in a time period of 3.5 s. what was the average acceleration?

the acceleration is a=3ms^-2

Step-by-step explanation:

The distance is =69.3m

Apply the equation of motion

v2=u2+2as

the initial velocity is u=5ms−1

The final velocity is v=21ms−1

The acceleration is a=3ms−2

The distance is

s=v2−u22a

=212−522⋅3

=26×166

18.8 cubic inches.

step-by-step explanation:

volume of a cone = πr²h

r = 1.5 inches

h = 8 inches

pi = 3.14

volume of our cone = × 3.14 × 1.5² × 8 = 18.84 square inches

or equals to 18.8 square inches rounded up to nearest tenth.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1