Apatient is given a 100-milligram dosage of a drug that decays exponentially at a rate of 11% per hour. the doctor wants to know when 15 milligrams of the drug remains. write an equation that models the situation. explain each aspect of your equation.

16.3 hours.

Step-by-step explanation:

"Decays exponentially at a rate of 11% per hour" translates into

(1 - 0.11)^h, where h is the number of hours during which the drug decays.

The negative sign comes from "decay."

The complete formula applicable here is

d(h) = (100 mg)(1 - 0.11)^h, where h is the number of hours.  

We want to know how many hours it will be until all but 15 mg remain.  The appropriate formula for this is

15 mg = (100 mg)()^h.  Dividing both sides by 100 mg, we get:

 15 mg

= 0.89^h, or 0.15 = 1.11^h

100 mg

Apply properties of logs to solve this.  Take the natural log of both sides of the above equation.  We get:

ln 0.15 = h(ln 0.89).  Dividing both sides by ln 0.89, we get:

h = 16.3

The original 100 mg dosage would decay to 15 mg after 16.3 hours.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)