Chapman’s brickyard sells brick and blocks. a brick costs .38 dollars and a block cost 1.56 dollars. the brickyard filled with a 24.80 dollars order, which contained 28 items

The number of bricks is 16 and the number of blocks is 12

Step-by-step explanation:

Let the number of bricks be x and blocks be y.

Cost of each brick = $0.38

Total cost of x bricks = 0.38*x

Cost of each block = $1.56

Total cost of y blocks = 1.56*y

Total amount spent for the brickyard = $24.80

So,

Total cost of x bricks + Total cost of y blocks = Total amount spent for the brickyard

=> 0.38x + 1.56y = 24.80 ____equation (1)

Total number of items (bricks+blocks) = 28

So,

Number of bricks + Number of blocks = Total number of items

=> x + y= 28 ____equation (2)

We will solve the two equations by the method of elimination.

Let's multiply equation 2 by -0.38

(-0.38)*x + (- 0.38)*y  = (-0.38)*(28)

=> -0.38x - 0.38y  = -10.64 ____equation (3)

Adding equation 1 to the equation 3, we get

-0.38x - 0.38y + 0.38x + 1.56y = -10.64 + 24.80

Cancelling out -0.38x and +0.38x on the left side, we get

1.56y - 0.38y = 24.80-10.64

=> 1.18y = 14.16

Dividing both sides by 1.18, we get

 =

=> y = 12

Plugging in y=12 in the equation 2, we get

x + y= 28

=> x + 12 =28

Subtracting 12 from both sides, we get

x+ 12 -12 = 28- 12

Cancelling out the +12 and -12 from the left side, we have

x = 16

So, the number of bricks is 16 and the number of blocks is 12.

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

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step-by-step explanation: