Asix-sided number cube is rolled. what is the probability of getting a 3 and then a 4, given that the first number rolled was a 3? 1. 1/3 2. 1/6 3. 1/36 4. 1/2

Option '2' is correct.

Step-by-step explanation:

Since we have given that

A six-sided number cube is rolled.

Let A be the event of getting the first number rolled was 3 .

Let B be the event of getting 4.

Probability of getting the first number rolled was 3 is given by

Probability of getting a 3 then a 4 is given by

so, our required probability is given by

Hence, Probability of getting a 3 and then a 4 given that the first number rolled was a 3 is

Therefore, Option '2' is correct.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

1.30

step-by-step explanation: