Prove whether or not the point (√21,2) lies on a circle centered at the origin and containing the point (5,0).

check the picture below.

so, we know the radius of this circle is 5 then, namely, the distance from (0,0) to (5,0) is 5.

now, if (√(21) , 2) indeed lies on that circle curve, then the distance from (0,0) to (√(21) , 2) will also be the same radius of 5 units.

It does. "Proof" below.

Step-by-step explanation:

In order for the given points to lie on the circle, they must both be the same distance from the origin. The Pythagorean theorem is used to make a "distance formula" for computing the distance between two points.

For a point (x, y), its distance (d) to the origin will be ...

... d = √(x² +y²)

For the reference point that we know is on the circle, this distance (the circle's radius) is ...

... d = √(5² +0²) = √25 = 5

For the point in question, the distance to the origin is ...

... d = √((√21)² +2²) = √(21 +4) = √25 = 5

Both points have the same distance to the origin, 5 units, so a circle (of radius 5) centered there will contain both points.

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A graph is not proof, but it can confirm the result.

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98