*30 points* in a group of 53 children, 22 had a dog, 18 had a cat, and 6 had both a dog and a cat. how many children had neither a dog nor a cat as a pet? a.)31 b.)19 c.)12 d.)37i've been stuck on this for idk how long. keep note that this question might be a typo, i'll update this later just in case it is.

7

Step-by-step explanation:

Although I don’t see that answer, with 53 children and 22 having a dog, 18 a cat, and 6 with both, you would think to subtract all three of those numbers with 53 to get the remaining with no dogs or cats, which results to 7

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!