In δabc, ad and be are the angle bisectors of ∠a and ∠b and de║ab. if m∠ade is with 34° smaller than m∠cab, find the measures of the angles of δade.

The measures of angles of Δ ADE are, m∠ ADE = m∠DAE= 34° and m∠DEA = 112°

Step-by-step explanation:

Here, AD and BE are the angle bisectors of ∠A and ∠B

Therefore, m∠BAD = m∠DAE = m∠ CAB/2 -------(1)

And, m∠ABE = m∠ EBD

Now, DE║AB

Therefore,  m∠BAD = m∠ ADE ( By the alternative interior angle theorem)

⇒ m∠ CAB/2 =m ∠ ADE -----------(2)

But given, m∠ CAB - m∠ ADE = 34°

⇒ m∠ CAB - m∠ CAB/2 = 34°

⇒m∠ CAB/2 = 34⇒ m∠CAB = 68°

⇒ m∠ ADE = 68°/2 = 34° ( By equation (2) )

And, m∠DAE = 34°

Since, in Δ ADE,

m∠ ADE + m∠DAE + m∠DEA = 180°

⇒ m∠DEA = 112°

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you