Mathematics, 29.06.2019 02:30 mamatonya5p5jl11
The equation of the circle whose center is at (2,1) and the radius is 3 is
Answers: 2
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{2}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{3}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-2)^2+(y-1)^2=3^2\implies (x-2)^2+(y-1)^2=9](/tpl/images/0029/3753/b6f85.png)
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