An artist drew a painting with proportional rectangles with the whole number dimensions in inches. the small rectangle is 8 inches by 3 inches. one dimension of the medium rectangle is 9 inches. one dimension of the large rectangle is 32 inches. what are the dimensions of the medium and large rectangle? medium= _ inches by 9 inches large = 32 inches by _ inches

Medium= 24 inches by 9 inches.Large = 32 inches by 12 inches.

Step-by-step explanation: Given an artist drew a painting with proportional rectangles with the whole number dimensions in inches.

Dimensions of small rectangle: 8 inches by 3 inches.

One dimension of medium rectangle is 9 inches.

Let us assume other dimension of the medium rectangle is x inches.

Therefore, we could setup a proportion:

On cross multiplying, we get

3x = 8×9

3x = 72.

Dividing both sides by 3, we get

3x/3 = 72/3

x = 24.

Therefore, Medium= 24 inches by 9 inches.

One dimension of large rectangle is 32 inches.

Let us assume other dimension of the medium rectangle is y inches.

Therefore, we could setup a proportion:

On cross multiplying, we get

8y = 32×3

8y = 96.

Dividing both sides by 8, we get

8y/8 = 96/8.

y = 12.

Therefore, Large = 32 inches by 12 inches.

The answer to this question is c

The correct answer will be d. -4