The base of a box is a rectangle. the width of the box is half its length. the height of the box is 0.5m. find the volume of the box if the area of the base is 1.08m² less than the combined area of the sides. (there are multiple answers)

 0.81 or 0.36

Step-by-step explanation:

Let length of the given cuboid = l

Therefore, according to the question,width of the cuboid = l/2

Now, the height of the cuboid = 0.5

Again according to the question,

The area of the base is 1.08m² less than the combined area of the sides.

Therefore, 2(l+l/2) ×0.5 - l×l/2 = 1.08

⇒

⇒

⇒

⇒ l = 1.2 m or 1.8 m

Thus, width of the cuboid = 0.6 m or 0.9 m

⇒ Therefore, the volume of the box, V = 1.2 × 0.6 × 0.5 or 1.8 × 0.9 × 0.5

⇒ V = 0.36 or 0.81

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source