Write the coordinate point for the vertex of this parabola x^2=12y

(0,0)

Step-by-step explanation:

the x coordinate for the vertex is at the line of symmetry

ax^2 +bx+c

the line of symmetry is at h =-b/2a

x^2 =12y

divide by 12

1/12 x^2 = y

a = 1/12  b=0 c=0

h = 0/(2* 1/12)

h =0

to find the y coordinate, substitute x=0 back in

y = 1/12 * 0 =  0

the vertex is (0,0)

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno

126 maybe. sorry