Given the line y = 1/3x + 2, write an equation in slope-intercept form of a perpendicular like that passes through (-2, -2).

y = -3x-8

Step-by-step explanation:

y = 1/3x +2

slope is 1/3

parallel is the negative reciprocal

m = -3

point slope form

y-y1 = m(x-x1)

y--2 = -3 (x--2)

y+2 = -3(x+2)

distribute

y+2 = -3x-6

subtract 2 from each side

y = -3x-6-2

y = -3x-8

slope is 35 and 20 miles is the y-intercept.

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form