Arectangle is 28 feet by 41 feet. if it can be determined, which of the following gives the whole number length, in feet, of a side of the largest square that will fit inside the rectangle?

c = 20 ft  

Step-by-step explanation:

The largest square will be 14 sqrt(2) ft long

To figure out the side length of the square

use the pythagorean theorem

a^2 + b^2 =c^2

we are limited by the shortest side of the rectangle

28 ft

each side of the triangle is 1/2 the length of the short side of the rectangle or 14 ft

a^2 + b^2 =c^2

14^2 + 14^2 = c^2  where c is the side of the square

196 + 196 = c^2

392 = c^2

take the square root of each side

sqrt(392) = sqrt(c^2)

c = 14sqrt(2)

c = 19.799ft

to the nearest whole number

c = 20 ft  

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

1696 hundred thousand

step-by-step explanation: