Complete the square to rewrite y=x^2-6x+15 in vertex form then state whether the vertex is a maximum or minimum and give its coordinates

y = (x - 3)² + 6,   vertex is a minimum (3, 6)

Step-by-step explanation:

y = x² - 6x + 15

-15               -15

y - 15 = x² - 6x

y - 15 +  9   = x² - 6x +   9  

              ↑             ↓        ↑

                              = -3, (-3)² = 9

y - 6 = (x - 3)²

y       = (x - 3)² + 6

answer for #1 is c

answer for #2 is d

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3 is greater then both of those numbers