The largest tree in the world is the general sherman sequoia in sequoia national park, california. it is 275 feet high, has a diameter of 36.5 feet, and has an estimated weight of 2,150 tons. find the sequoia’s circumference to the nearest tenth of a foot. use 3.14 for π. explain how you found the answer.

114.6 ft

Step-by-step explanation:

The circumference is found by multiplying the diameter by pi.

... C = πd

... C = 3.14×36.5 ft = 114.61 ft

Since the product has two decimal places, it must be rounded to express it to the nearest tenth foot. The hundredths digit is less than 5, so it is merely dropped.

... 114.61 ft ≈ 114.6 ft

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

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