Write the first five terms of the sequence defined by the recursive formula a_n=(5a_n-1)-1, with a_1=0

a_1 = 0

a_2 = -1

a_3 = -6

a_4 = -31

a_5 = -156

Step-by-step explanation:

a_n=(5a_n-1)-1

a_1 = 0

to find a2  substitute a1

a_2 = (5* a_1)-1

a_2 = 5* 0 -1

a_2 = 0-1

a_2 = -1

to find a3  substitute a2

a_3 = (5* a_2)-1

a_3 = (5* -1 ) -1

a_3 = -5 -1

a_3 = -6

to find a4  substitute a3

a_4 = (5* a_3)-1

a_4 = (5* -6 ) -1

a_4 = -30 -1

a_4 = -31

to find a5  substitute a4

a_5 = (5* a_4)-1

a_5 = (5* -31 ) -1

a_5 = -155 -1

a_5 = -156

yes, the other person's answer is right! :)

i used to know but i learned it a long time ago sorry

step-by-step explanation:

(x+3)(x+7)

step-by-step explanation: