Kite qrst has a short diagonal of qs and a long diagonal of rt. the diagonals intersect at point p. side qr= 5 m and diagonal qs= 6m. find the length of segment rp

Given the statement: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P.

Properties of Kite:

It is given that: Side QR = 5m and diagonal QS = 6m.

Then, by properties of kite:

Substitute the value of QS we get QP;

= 3 m

Now, in right angle

Using Pythagoras theorem:

Substitute the given values we get;

or

Subtract 9 from both sides we get;

Simplify:

Therefore, the length of segment RP is, 4m

Step-by-step explanation:

Firstly, we will draw diagram  for kite

we are given

QR=5m

QS=6m

we know that QPR is a right angled triangle

so, QP=PS

now, we can use Pythagoras theorem

now, we can plug values

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

he kicked it up? is this the answer ?

step-by-step explanation: