What is the solution set of the quadratic inequality x^2+x-2> 0

(-∞, -2) U (1, ∞)

Step-by-step explanation:

    x² + x - 2 > 0

First, find the zeros by setting the equation EQUAL to zero:

   x² + x - 2 = 0

 (x + 2)(x - 1) = 0

x + 2 = 0    x - 1 = 0

  x = -2        x = 1

Next, choose a test point to the left, between, and to the right of the zeros and check to see if the test points are positive (greater than zero)

Left (x = -3):    (-3 + 2)(-3 - 1) = (-)(-) = +

Between (x = 0):   (0 + 2)(0 - 1) = (+)(-) = -

Right (x = 2):   (2 + 2)(2 - 1) = (+)(+) = +

The left and right test points are positive (greater than zero) so the solution is x < -2 and x > 1

Interval Notation: (-∞, -2) U (1, ∞)

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.