What is the solution of the system of linear equations below? 2x-6y=12 -x+3y=-2 a. (0,-2) b. (-2,0) c. no solution d. (6,0) plsss asap im doin a mastery test on plato ! 14 points !

The answer C i.e. no solution is the right answer

Step-by-step explanation:

Given  system of equations:

2x-6y=12 [1]

-x+3y=-2 [2]

When we multiply the second equation by 2

we get

-2x+6y=-4

Multiplying both sides by -1

2x-6y=4 [3]

On comparing [1] and [3]

we see that their coefficients of variables are same but the value

on the other side is different

which is not possible for a equation

Hence the system has no solution

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?