Find the equation of the line passing through the given point and perpendicular to the given equation write your answer in slope intercept form

Slope-intercept form:

y = mx + b      "m" is the slope, "b" is the y-intercept

For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2

3.) y = 2x - 2

The given line's slope is 2, so the perpendicular line's slope is -1/2

To find "b", plug in the point (-5 , 5) into the equation

    Subtract 5/2 on both sides

  Make the denominators the same

4.) -6x + 5y = -10     Get "y" by itself, add 6x on both sides

5y = -10 + 6x          Divide 5 on both sides

The given line's slope is 6/5, so the perpendicular line's slope is -5/6.

      Plug in (-2, 5)

   Subtract 5/3 on both sides

   Make the denominators the same

7.) Perpendicular line's slope is -2

y = -2x + b      Plug in (1,4)

4 = -2(1) + b

4 = -2 + b

6 = b

y = -2x + 6

8.) Perpendicular line's slope is -1/4

    Plug in (-5 , 2)

   Subtract 5/4 on both sides

    Make the denominators the same

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.