Will mark ! find tan θ if cos θ = one divided by four and sin θ < 0. a. negative square root of fifteen b.4 c. negative square root of fifteen divided by fifteen d. negative square root of seventeen

-3.872983346

Step-by-step explanation:

In this case we have: cos θ = 1/4 Whose possible solutions are: θ = 2 * pi * n - Acos (1/4) θ = 2 * pi * n + Acos (1/4) Where, n belongs to the natural numbers. As sin θ <0 then the solution is: θ = 2 * pi * n - Acos (1/4) For n = 1 we get: θ = 4.965069236 radians Thus: tan θ = tan (4.965069236) = - 3.872983346 tan θ = -3.872983346

A. negative square root of fifteen

Step-by-step explanation:

In this case we have: cos θ = 1/4 Whose possible solutions are: θ = 2 * pi * n - Acos (1/4) θ = 2 * pi * n + Acos (1/4) Where, n belongs to the natural numbers. As sin θ <0 then the solution is: θ = 2 * pi * n - Acos (1/4) For n = 1 we get: θ = 4.965069236 radians Thus: tan θ = tan (4.965069236) = - 3.872983346 tan θ = -3.872983346 = negative square root of fifteen

THE GUY/GIRL BEFORE ANSWERED CORRECTLY

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the value of x is 28.2