Aparticle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). find the acceleration of the particle when the velocity is first zero 5e 5e^2 e none of these

Step-by-step explanation:

we are given equation for position function as

Since, we have to find acceleration

For finding acceleration , we will find second derivative

now, we can find derivative again

Firstly, we will set velocity =0

and then we can solve for t

we get

now, we can plug that into acceleration

and we get

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.

x = 3 ± √(5+y)