What is the slope intercept of a line perpendicular to the line y=2x+3 with the point (-2,-4)

y = - x - 5

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = 2x + 3 is in this form with slope m = 2

given a line with slope m then the slope of a line perpendicular to it is

= - = -

y = - x + c ← is the partial equation

To find c substitute (- 2, - 4) into the partial equation

- 4 = 1 + c ⇒ c = - 4 - 1 = - 5

y = - x - 5 ← equation of perpendicular line

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol