Circle o is inscribed in abc. what is the perimeter of abc

Since O is inscribed in triangle ABC, you know that AB, AC, and BC are all tangent to the circle. The tangent segments theorem asserts that AD is congruent to A F; BD is congruent to BE; and CF is congruent to CE. (NOTE: E is the point where the circle touches BC - I've taken the liberty of labeling it as such.)

Then the perimeter of triangle ABC will be twice the sum of the labeled edges:

answer: hey there,

the answer you are looking for is a..

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