Is it possible to solve a quadratic equation that is not factorable over the set of integers? explain.

YES, it is possible to solve a quadratic equation that is not factorable over the set of integers.

Step-by-step explanation:

A quadratic equation is a condition of the second degree, which means it contains no less than one term that is squared. The standard frame is

ax² + bx + c = 0

with a, b, and c being constants or numerical coefficients, and x is an obscure variable.

The quadratic equation includes just a single obscure, it is designated "univariate". Specifically, it is a second-degree polynomial condition, since the best power is two.

Whenever factorization fails you can use:

a) completing the square method  

b) quadratic formula

to solve the quadratic equation.

The answers can lead you to the complex numbers but there is always a solution.

-6 is the correct option from the above given options

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is