[15 points] me! 1) write the equation in slope-intercept form that contains the following point with the given slope. slope= 2 ; (-3, 1) 2) tell me which lines are parallel to each other. -6x + 2y = 8; y = 4; y = 3x; y = 3

1) y=2x+7      2) y=4 and y=3

Step-by-step explanation:

1) you start knowing that the slope-intercept equation is y=mx+b. M stands for your slope so you just plug 2 in for m. Then you plug in the x to see how to make it equal 1. As you look at it you realize that 2*-3 is -6 and you need to add 7 to get to one. Therefore the seven would be the B.

2) Since there is no slope the lines just go on the horizon at the y point of 4 or 3.

there is no graph so i cant sorry

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.