Tim worker is doing his budget. he discovers that the average electric bill for the year was $206 with a standard deviation of $10.00. what percent of his expenses in this category would he expect to fall between $184.00 and $200.00? the z for $184.00 = - .62.22 the percent of area associated with $184.00 = 62.2 the z for $200 = - .622.22 the percent of area associated with $200 = 48.6 subtracting the two percentages, the percent of expenses between $184.00 and $200.00 is 622.22 you in advance for your .god bless you all

Step-by-step explanation:

Z is computed from ...

... z = (x -μ)/σ

Our lower limit for x is 184, so its z-value is ...

... z = (184 -206)/10 = -22/10 = -2.2

Our upper limit for x is 200, so its z-value is ...

... z = (200 -206)/10 = -6/10 = -0.6

A suitable table or probability calculator can tell you ...

... the percent of area associated with z = -2.2 is about 1.4%. That is, about 1.4% of all values lie below z = -2.2.

... the percent of area associated with z = -0.6 is about 27.4%.

The fraction of expenses between $184 and $200 is then calculated to be ...

... 27.4% - 1.4% = 26.0%

ok

step-by-step explanation: