Writ an equation of the line perpendicular to y+1=5/3(x+5) through the point (-6,-10 show all work

y +10 = (-3/5)(x +6)

Step-by-step explanation:

The slope of the given line can be read from its point-slope form as 5/3. The slope of a perpendicular line will be the opposite of the reciprocal of that, so will be -1/(5/3) = -3/5.

Using your given point in the point-slope form of the equation of a line, your equation is ...

... y -(-10) = (-3/5)(x -(-6))

... y + 10 = (-3/5)(x +6) . . . . . simplified

move it to the other side

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)