I'm having trouble figuring out what the equation is for the trend line and what the slope is

The equation for the trend line would be y = -1/100x + 25

Step-by-step explanation:

In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (0 - 25)/(2500 - 5)

m = -25/2500

m = -1/100

Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.

y = mx + b

y = -1/100x + 25

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

you can download it here